0=12x^2-88x+105

Solution for 0=12x^2-88x+105 equation:

0=12x^2-88x+105

We move all terms to the left:

0-(12x^2-88x+105)=0

We add all the numbers together, and all the variables

-(12x^2-88x+105)=0

We get rid of parentheses

-12x^2+88x-105=0

a = -12; b = 88; c = -105;
Δ = b2-4ac
Δ = 882-4·(-12)·(-105)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-52}{2*-12}=\frac{-140}{-24}
=5+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+52}{2*-12}=\frac{-36}{-24}
=1+1/2
$